Meter-Gram Force (m g) to Foot-Poundal (ft pdl) converter

Converting from Meter-Gram Force (m g) to Foot-Poundal (ft pdl)

What is Meter-Gram Force (m g)

Meter-Gram Force (m g) is a unit of torque in the CGS (centimeter-gram-second) system. It is defined as the force exerted by one gram mass at a distance of one meter from the axis of rotation.

What is Foot-Poundal (ft pdl)

Foot-Poundal (ft pdl) is a unit of torque in the FPS (foot-pound-second) system. It is defined as the force required to accelerate one pound mass at one foot per second squared.

Conversion Formulas

To convert from Meter-Gram Force (m g) to Foot-Poundal (ft pdl), you can use the following formulas:

  • 1(mg)=0.2327153(ftpdl)

  • ft pdl=4.297095×m g

Examples

  1. Convert 12 m g to ft pdl:

    • 12 m g=12×0.2327153 ft pdl=2.792584 ft pdl
  2. Convert 16 m g to ft pdl:

    • 16 m g=16×0.2327153 ft pdl=3.723445 ft pdl
  3. Convert 6 ft pdl to m g:

    • 6 ft pdl=6×4.297095 m g=25.78257 m g

Conclusion

Use these conversion formulas and examples to easily convert between Meter-Gram Force (m g) and Foot-Poundal (ft pdl) units.

Meter-Gram Force to Foot-Poundal conversion table

m g to ft pdl conversion table

Meter-Gram Force (m g)Foot-Poundal (ft pdl)
0.01 m g0.002327153 ft pdl
0.1 m g0.02327153 ft pdl
1 m g0.2327153 ft pdl
2 m g0.4654307 ft pdl
3 m g0.698146 ft pdl
4 m g0.9308614 ft pdl
5 m g1.163577 ft pdl
6 m g1.396292 ft pdl
7 m g1.629007 ft pdl
8 m g1.861723 ft pdl
9 m g2.094438 ft pdl
10 m g2.327153 ft pdl
10 m g2.327153 ft pdl
20 m g4.654307 ft pdl
30 m g6.98146 ft pdl
40 m g9.308614 ft pdl
50 m g11.63577 ft pdl
60 m g13.96292 ft pdl
70 m g16.29007 ft pdl
80 m g18.61723 ft pdl
90 m g20.94438 ft pdl
100 m g23.27153 ft pdl
1 000 m g232.7153 ft pdl
2 000 m g465.4307 ft pdl
3 000 m g698.146 ft pdl
4 000 m g930.8614 ft pdl
5 000 m g1 163.577 ft pdl
6 000 m g1 396.292 ft pdl
7 000 m g1 629.007 ft pdl
8 000 m g1 861.723 ft pdl
9 000 m g2 094.438 ft pdl
10 000 m g2 327.153 ft pdl